azonosító nélkül?
";
$ref = $_SERVER['HTTP_REFERER'];
header( 'refresh: 1; url='.$ref);
}
?>
Result
ezek lettek:
";
//
// $parancs3 = "SELECT cult_id , hun_title, title, year FROM books WHERE cult_id ='" . $cult_id ."' " ;
// $eredmeny3 = mysql_query($parancs3, $conn) or die("Nem tudtam az adatokat lek�rni. A hiba oka: ".mysql_error());
//
//
// $adminbooktext=""; //adminloghoz;
//
// while ( $sor = mysql_fetch_array($eredmeny3)) {
// $adminbooktext.=$sor['title'];
// $adminbooktext.=" // ".$sor['hun_title'];
//
// $adminbooktext.=" (". $sor['year'].")";
// }
// date_default_timezone_set('Europe/Budapest');
// $datetime = date("y-m-d G:i:s");
// $action_id=351;
// $object_id=$tag_id;
// $object_2_id=$cult_id ;
// $value_text="C�mke t�rl�se: ".$tagtext." || Err�l a filmr�l: ".$adminbooktext;
//
// $parancs = "INSERT INTO admin_log (nick, action_id, object_id, object_2_id, value, datetime) VALUES ('".$_SESSION['nick']."', '" . $action_id . "', '" . $object_id . "','" . $object_2_id . "', \"" . $value_text . "\", '" . $datetime . "') ;" ;
// $eredmeny = mysql_query($parancs, $conn) or die("Nem tudtam az adatokat lek�rni. A hiba oka: ".mysql_error());
$ref = "cultcharacter.php?id=".$cult_id ;
print "
Nézzük meg kivette-e";
echo "";
include 'closedb.php';
?>